Instruction
For each question, you must clearly show ALL your work for full credit.
Part 1 : solidworks Design a the hip implant on the image below in solidworks Save the file and submit ( YOU DONOT NEED TO WRITE A REPORT, just include the solidworks design.
Part 2 : biotransport For each question, you must clearly show ALL your work for full credit. 1. Helium and nitrogen gas are contained in a conduit 5mm in diameter and 0.1m long at 298 K with a uniform constant pressure of 1.0 atm. The partial pressure of He at one end of the tube is 0.060 and at the other end it is 0.020 atm. The diffusivity is 0.687 x 10-4 m2/s.
Calculate the following for steady-state equimolar counterdiffusion: a. Flux of He in kg mol/s*m2 ANSWER: 1.124 x 10-6 b. Flux of N3 ANSWER: -1.124 x 10-6 c. Partial pressure of He at a point 0.05m from either end. ANSWER: 0.040 atm 2. Ammonia gas is diffusing through N2 under steady-state conditions with N2 nondiffusing since it is insoluble in one boundary. The total pressure is 1.013 x 105 Pa and the temperature is 298 K The partial pressure of NH3 at one point is 1.333 x 104 Pa, and at the other point 20mm away it is 6.666 x 103 Pa. The DAB for the mixture is 2.30 x 10-5 m2/s. a. Calculate the flux of NH4 in kg mol/m2*s. ANSWER 3.44 x 10-6 kg mol/ s*m2 b. Do the same as (a) but assume N2 also diffuses; that is, both boundaries are permeable to both gases and the flux is equimolar counterdiffusion. In which case is the flux greater? ANSWER 3.10 x 10-6 kg mol/ s*m2 3. The solute HCl (A) is diffusing through a thin film of water (B) 2.0 mm thick at 283K. The concentration of HCl at point 1 at one boundary of the film is 12.0 wt% HCl (ρ1= 1060.7 kg/m3), and at the other boundary at point 2 it is 6.0 wt % HCl (ρ2= 1030.3 kg/m3). The diffusion coefficient of HCl in water is 2.5 x 10-9 m2/s. Assuming steady-state and “one boundary impermeable to water”, calculate the flux of HCl. ANSWER: 2.372 x 10-6 kg mol/s*m2 4. Pure hydrogen gas at 2.0 atm pressure and 27°C is flowing past a vulcanized neoprene rubber slab 5mm thick. Calculate the flux at steady state as the gas diffuses through the rubber slab. You may assume the partial pressure of H2 on the other side of the slab is zero. The diffusivity is 0.180 x 10-9 m2/s and the solubility is 0.053 m3 solute (STP)/ m3 solid *atm. ANSWER: 1.703 x 10-10 kg mol/ s*m2 5. A value of kG was experimentally determined to be 1.3462 x 10-3 kg mol/ s*m2*atm for A diffusing through stagnant B. For the same flow and concentrations, it is desired to predict k’G and the flux of A for equimolar counterdiffusion. The partial pressures of A are pA1= 0.20 atm, pA2 = 0.05atm. The total pressure of the system is P= 1.0 atm. ANSWERS: k’G= 1.1175 x 10-3 kg mol/ s*m2*atm, NA= 1.7625 x 10-3 kg mol/s*m2