6 pre calculus / trig review questions

Thanks, I just assigned it to you. I have done the problems but don't have much faith in my answers so I look forward to seeing what you have.
User_3759 | Aug 31, 2014, 00:28 AM

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Do you just want the answers then, and then any that i have that disagree with yours i can show you my full solution? Or would you just like the full solution for all of them?
User_3378 | Aug 31, 2014, 00:31 AM

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i already have all the answers, i'm just in the process of putting it together neatly for you. So i can send all of it, full solutions explained, in a little while anyway.
User_3378 | Aug 31, 2014, 00:38 AM

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Thank you. Send all of it that way I can just compare.
User_3759 | Aug 31, 2014, 00:47 AM

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OK, i will do that.
User_3378 | Aug 31, 2014, 00:50 AM

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i uploaded a PDF with my solutions and answers. Please let me know if you have any problems with it, or need any clarifications.
User_3378 | Aug 31, 2014, 01:52 AM

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thank you, i wont be able to look at it until later but a quick scan it looks good. # 2 i got right but could not remember how I did it, thanks for the explanation! I released payment.
User_3759 | Aug 31, 2014, 02:21 AM

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Thanks a lot. I missed # 1 and did not consider the open and closed point on #6. I do have a question if you have the time to answer, if not that is fine as well. On question #2 I stumbled on a formula I used but cannot remember where I found it and what its relevance is. If possible could you give me the name of this formula (regarding question #2: y = 2 + m( x - 1) y = 2+ mx - m y = 2 + ax - a 2 + mx -m = 2 + ax - a mx - m = m - a and so on.... finally I am posting another request it is for some random questions in my text book. The book has answers for the odd questions but not how the answers were derived. I have selected 42 from the first 3 sections. If I can get it early enough I can use it to study for my first quiz. Math has always been a struggle for me, so I am trying a different approach this year in hopes of better results. please take a look at it and let me know what your price is, if any. Since it is for my own quiz prep, it has value to me but how much I do not know. Thanks again for you help.
User_3759 | Aug 31, 2014, 06:18 AM

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Is this the sequence of equations you meant? y = 2 + m( x - 1) y = 2+ mx - m y = 2 + ax - a 2 + mx -m = 2 + ax - a mx - m = m - a i'm not sure where you would have found this or what its name is. (Was it from your book, perhaps?) It looks like it might just be a way to come up with a general description of the line, but i'm not sure what's happening on that last step. Going back one from there the way i would see it proceeding would be: 2 + mx -m = 2 + ax - a mx - m = ax - a But this is really just a way of replacing m with a, because you can factor m on the left and a on the right and then cancel the (x - 1) m(x - 1) = a(x - 1) --> m = a ...so i'm not sure what the intent is. Whether it's m or a doesn't really matter, because in either case you can replace the variable with any number you choose. Sorry i can't be more specific...if you happen to remember where you found it, maybe some context would help me figure out what was intended by the source. Regarding the other assignment, as soon as you post it, i'll take a look at it and get back to you. Let me know how early would be early enough for you.
User_3378 | Aug 31, 2014, 06:46 AM

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i can't see anything on the file you attached to the other assignment. i downloaded the file but none of the programs i had could open the odt file. i downloaded an odt viewer program, but when i opened the file it was blank, or whatever content was there was not showing up correctly (just blank boxes). Any way you could just upload the individual images, of the textbook pages, or are there too many of them?
User_3378 | Aug 31, 2014, 07:00 AM

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thanks for the heads up, I used open-office for that file. I will redo it tomorrow with pdf, word or maybe paint. With regards to the question I had on my first assignment, I found it somewhere online ( I visited lots of sites before posting here). I probably just found a similar example and imitated it. No worries thanks again.
User_3759 | Aug 31, 2014, 07:14 AM

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OK. i'll check back for the new file tomorrow then.
User_3378 | Aug 31, 2014, 07:36 AM

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The only reason i want to see the problems first is to make absolutely sure i'll have time to finish all of it by the time you need it. i don't want to bid before then because i don't want to promise something i can't do. But if i can verify that i'll be able to finish what you need in time, i will definitely bid.
User_3378 | Aug 31, 2014, 07:49 AM

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i downloaded Open Office and now i can see it, so don't worry about reuploading.
User_3378 | Aug 31, 2014, 20:52 PM

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Hello rednu, I hate to beat a dead horse but can you try and explain one more time how you pulled the common point (1,2) from the equation y = 2 +m(x - 1) ?
User_3759 | Feb 09, 2014, 00:19 AM

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x = 1 makes (x - 1) = 0 and therefore m(x - 1) = 0, regardless of the value of m. This leaves you with y = 2. So therefore, whenever x = 1, no matter what m is, y = 2. This produces the common point (1, 2).
User_3378 | Feb 09, 2014, 05:31 AM

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