NEEDS TO BE IN STANDARD ANCI in .c code INTRODUCTION: When electricity is transmitted through voltage lines, losses occur due to electrons colliding, converting their energy into heat. To minimize these losses, generally current is transmitted over long distances at high voltage; higher currents lead to heat losses, and low currents require high voltage (Ohm's law). These losses scale with the square of a wire's current. (As a note: this is why AC current is used in power transmission - it is less lossy than DC current.) The power loss can be calculated using the following equations: where: i = current (amps) r = resistance (ohms/mile) R = total resistance (ohms) ASSIGNMENT: Write a C program that will first allow the user to enter the line resistance in ohms/mile and the power transmitted in kW. The program needs to ensure that line resistance is between 0.04 and 0.07 ohms/mile and power transmitted is between 475 and 525 kW; if either of these is not, it should print an error message and the program should end. If the values are acceptable, the program should compute the power loss for power transmitted from a station to cities at distances of 15, 30, 45, ..., 150 miles at 100 V and 200 V. Use a while loop to control voltage (initialize at 100.0 and increment by 100.0 to 200.0) and a nested for loop to control distance (initialize at 15.0 and increment by 15.0 to 150.0). The voltage, distance, and power loss should print to the screen. Your program output will look like the illustration shown below. Use your PC's cursor to determine the horizontal and vertical spacing for the output format. NOTE: Use proper variable names. No single letter variables will be accepted. SAMPLE OUTPUT FORMAT: ******************************************** POWER LOSS IN TRANSMISSION LINE Enter line resistance in ohms/mile: x Enter transmitted power in kW : x RESULTS Voltage = 100.0 volts Distance (mi) Power loss (Watts) 15.0 X.XXXEXXXX 30.0 X.XXXEXXXX 45.0 X.XXXEXXXX 60.0 X.XXXEXXXX . . . . . . 150.0 X.XXXEXXXX Voltage = 200.0 volts Distance (mi) Power loss (Watts) 15.0 X.XXXEXXXX 30.0 X.XXXEXXXX 45.0 X.XXXEXXXX 60.0 X.XXXEXXXX . . . . . . 150.0 X.XXXEXXXX ********************************************

NEEDS TO BE IN STANDARD ANCI in .c code INTRODUCTION: When electricity is transmitted through voltage lines, losses occur due to electrons colliding, converting their energy into heat. To minimize these losses, generally current is transmitted over long distances at high voltage; higher currents lead to heat losses, and low currents require high voltage (Ohm's law). These losses scale with the square of a wire's current. (As a note: this is why AC current is used in power transmission - it is less lossy than DC current.) The power loss can be calculated using the following equations: where: i = current (amps) r = resistance (ohms/mile) R = total resistance (ohms) ASSIGNMENT: Write a C program that will first allow the user to enter the line resistance in ohms/mile and the power transmitted in kW. The program needs to ensure that line resistance is between 0.04 and 0.07 ohms/mile and power transmitted is between 475 and 525 kW; if either of these is not, it should print an error message and the program should end. If the values are acceptable, the program should compute the power loss for power transmitted from a station to cities at distances of 15, 30, 45, ..., 150 miles at 100 V and 200 V. Use a while loop to control voltage (initialize at 100.0 and increment by 100.0 to 200.0) and a nested for loop to control distance (initialize at 15.0 and increment by 15.0 to 150.0). The voltage, distance, and power loss should print to the screen. Your program output will look like the illustration shown below. Use your PC's cursor to determine the horizontal and vertical spacing for the output format. NOTE: Use proper variable names. No single letter variables will be accepted. SAMPLE OUTPUT FORMAT: ******************************************** POWER LOSS IN TRANSMISSION LINE Enter line resistance in ohms/mile: x Enter transmitted power in kW : x RESULTS Voltage = 100.0 volts Distance (mi) Power loss (Watts) 15.0 X.XXXEXXXX 30.0 X.XXXEXXXX 45.0 X.XXXEXXXX 60.0 X.XXXEXXXX . . . . . . 150.0 X.XXXEXXXX Voltage = 200.0 volts Distance (mi) Power loss (Watts) 15.0 X.XXXEXXXX 30.0 X.XXXEXXXX 45.0 X.XXXEXXXX 60.0 X.XXXEXXXX . . . . . . 150.0 X.XXXEXXXX ********************************************