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Vinegar is a roughly 0.832 M solution of acetic acid in water. You have to quickly make 780 mL of vinegar and all you have is 20.0 g of acetic acid, distilled water, and and 1 L bottle of 0.500 M CH3COOH (aq). What are the steps to achieve this goal?

Date Posted: 02/09/2018
Category: Chemistry
Due Date: 04/09/2018
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  • The 20.0 g is of pure acetic acid.
    User_16786 | Sep 03, 2018, 05:12 AM
  • Can you do it before Tuesday please?
    User_16786 | Sep 03, 2018, 05:26 AM
  • Thanks for assigning it to me. I will work on it and let you know when I complete it.
    IvyleagueGirl | Sep 03, 2018, 07:47 AM
  • When will you be done?
    User_16786 | Sep 03, 2018, 16:35 PM
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    User_16786 | Sep 03, 2018, 18:53 PM
  • Hi. Check the image that I have uploaded. Do you want me to write the work in Microsoft Word file?
    IvyleagueGirl | Sep 03, 2018, 19:04 PM
  • So if I add the 20.0 grams of pure acetic acid to the 0.500 M solution of CH3COOH (aq) till it acquires the same number of grams that the 0.832 M solution of CH3COOH (aq) the 0.500 solution will become a 0.832 M solution and I'll just have to take 780 mL of the solution?
    User_16786 | Sep 03, 2018, 19:41 PM
  • Yes.
    IvyleagueGirl | Sep 03, 2018, 19:43 PM
  • Thank you very much!
    User_16786 | Sep 03, 2018, 19:54 PM
  • You are welcome. Please release the payment for this work.
    IvyleagueGirl | Sep 03, 2018, 19:55 PM
  • Done
    User_16786 | Sep 03, 2018, 19:56 PM
  • Thanks for releasing the payment for this work. Whenever you post a new assignment in future, please notify me here by sending a message and I will be ready and glad to do it for you. Thank you.
    IvyleagueGirl | Sep 03, 2018, 19:57 PM
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