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ELEMENTARY STATISTICS- Work out the following problems. Show your work. No partial credit will be given without work shown, even if the answer is correct.

Date Posted: 12/03/2020
Category: Other
Due Date: 12/03/2020
Instruction
THIS IS VERY EASY TASK, BUT I NEED SOMEONE TO HELP ME DO THIS SINCE I HAVE NO TIME FOR DOING THIS. DEADLINE IN 18 HOURS (NOW IS AT 8 PM AND IT SHOULD BE FINISHED MAXIMUM AT 2 PM). I THINK YOU COULD DO IT IN LESS THAN 45 MINS. PLEASE SHOW YOUR WORK. THANK YOU. SEE THE FILE THAT I HAVE ATTACHED.
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Download File 3 (xlsx)
Bidders
Euphrates 6 years, 6 months ago
Rated 9.44 earned 62853.11 around 1902 assignments.
Hello
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qualitywriter 6 years, 6 months ago
Rated 9.35 earned 2849.47 around 110 assignments.
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Javawriter 6 years, 6 months ago
Rated 8.81 earned 69150.66 around 2092 assignments.
Hey..I can Help you in this friend. Thank you
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SolutionASAP 6 years, 6 months ago
Rated 8.96 earned 13184.04 around 380 assignments.
Having gone through your assignment instructions, I can guarantee a well-structured high quality solution delivered in a timely manner. Feel free to message me. Let's talk.
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  • I can do this within 2 hours. Please hire me
    SolutionASAP | Mar 12, 2020, 02:57 AM
  • Are you there?
    SolutionASAP | Mar 12, 2020, 02:58 AM
  • I have started working on it and revert 100% accurate solutions within 2 hours. Hire me
    SolutionASAP | Mar 12, 2020, 03:00 AM
  • Are you sure that you can give me a perfect score?
    User_24281 | Mar 12, 2020, 03:01 AM
  • Question #2 claim: p = 0.08Alternative: p 0.08Hypothesis test: H0: p = 0.08H1: p 0.03Test statistic: z =47)92.0(08.008.0ˆ479npqpp2.8174P-value: = 2 Normalcdf(2.8174, ∞, 0,1) 0.0048< 0.05Reject H0Final conclusion: Thereis sufficient evidence to warrant rejection of the claim that p = 0.08
    SolutionASAP | Mar 12, 2020, 03:01 AM
  • Okay, I trust you
    User_24281 | Mar 12, 2020, 03:02 AM
  • Question #2 finished . Please hire me and I can send you proper solutions with neatly typed into word file.
    SolutionASAP | Mar 12, 2020, 03:02 AM
  • I have already assigned you fellas
    User_24281 | Mar 12, 2020, 03:04 AM
  • Good luck!! Give me your best shot! I really need full score to boost my grade. Thank you!!!
    User_24281 | Mar 12, 2020, 03:04 AM
  • Super. I can do well and revert you within an hour.
    SolutionASAP | Mar 12, 2020, 03:04 AM
  • Do not forget to show your work!! Thank you
    User_24281 | Mar 12, 2020, 03:07 AM
  • You are the best
    User_24281 | Mar 12, 2020, 03:07 AM
  • Attached file is the answers. Please check and leave 10/10 ratings with good comments about my services.
    SolutionASAP | Mar 12, 2020, 04:23 AM
  • P-value: = 2 Normalcdf(2.82, ∞, 0,1)= 0.0048 What does it mean? Normalcdf?
    User_24281 | Mar 12, 2020, 04:29 AM
  • I usually use 2 x P(Z<... OR Z>...) OR P(1-Z(P)) or something like that
    User_24281 | Mar 12, 2020, 04:30 AM
  • Let me check and revert you
    SolutionASAP | Mar 12, 2020, 04:32 AM
  • We can use P(1-Z(P)): 2*P(1-Z(P))=2*(1-0.998)=0.005 Are you happy now?
    SolutionASAP | Mar 12, 2020, 04:33 AM
  • Please release my payment with 10/10 ratings with good comments about my work.
    SolutionASAP | Mar 12, 2020, 04:34 AM
  • Hello, I will give you more bonus
    User_24281 | Mar 12, 2020, 04:42 AM
  • Can you edit the answer so it is similar to my prof's style
    User_24281 | Mar 12, 2020, 04:42 AM
  • I have attached the pdf of the example of my prof's notes
    User_24281 | Mar 12, 2020, 04:42 AM
  • Also, you have not interpret. See the example friend
    User_24281 | Mar 12, 2020, 04:43 AM
  • Sure. Send me your friend answers too.
    SolutionASAP | Mar 12, 2020, 04:44 AM
  • Just make it similar to the steps in the pdf, like the way my prof interpret. Just follow the guidelines
    User_24281 | Mar 12, 2020, 04:46 AM
  • Again, I have added all the points as per your prof's notes and but, writing style bit different. Now worried about my solutions and 100% accurate.
    SolutionASAP | Mar 12, 2020, 04:51 AM
  • Again, I have added all the points as per your prof's notes and but, writing style bit different. No worried about my solutions and 100% accurate.
    SolutionASAP | Mar 12, 2020, 04:51 AM
  • I have checked your calculation with my friend; we got the same answer. However, for the question number 1, my friend use t rather than z because he says that the data is sample means. What do you think about it?
    User_24281 | Mar 12, 2020, 04:53 AM
  • Also, you have not answered for the "interpret"
    User_24281 | Mar 12, 2020, 04:55 AM
  • It is concept of Standardized test statistics for large sample hypothesis test concerning a single population mean. Give me sometime, let add similar to prof's and revert.
    SolutionASAP | Mar 12, 2020, 04:59 AM
  • You still have 6 hours to finish it. Take your time!
    User_24281 | Mar 12, 2020, 05:00 AM
  • I give you bonus because I like your hardwork
    User_24281 | Mar 12, 2020, 05:09 AM
  • I am willing to give you more bonus if you really make me satisfied to your work
    User_24281 | Mar 12, 2020, 05:10 AM
  • Good luck friend!
    User_24281 | Mar 12, 2020, 05:10 AM
  • I have corrected and added too. Please check and let me know any changes.
    SolutionASAP | Mar 12, 2020, 07:04 AM
  • Give me 24 hours, and I will release your payment friend. Thank you!!
    User_24281 | Mar 12, 2020, 17:53 PM
  • = P(1-Z(P)): 2*P(1-Z(P))=2*(1-0.998)=0.0048 How do you get the 0.0048? There must be a symbol that is missing or something like that
    User_24281 | Mar 12, 2020, 18:02 PM
  • My friend answer like this: z-statistic = (9/47-0.080)/√(0.08*0.92/47)=2.817 p-value = P(|Z|>2.817)=0.0048 Answer: p-value =0.0048
    User_24281 | Mar 12, 2020, 18:04 PM
  • Can you fix one more time, and you are done
    User_24281 | Mar 12, 2020, 18:04 PM
  • Thank you
    User_24281 | Mar 12, 2020, 18:04 PM
  • z=2.817 P-value=2*(1-P(z))=2*(1-P(z=2.817)=2*(1-0.998)=2*0.005=0.0048
    SolutionASAP | Mar 13, 2020, 00:11 AM
  • Wait.. if I see the equation like that, what in my mind is 1-0.998 is 0.002, and then, 0.002 times 2 so the result is 0.004. Also where is the symbol < or >; I am only confused in that part.
    User_24281 | Mar 13, 2020, 00:23 AM
  • Decimal issue: z=2.817 P-value=2*(1-P(z))=2*(1-P(z=2.817)=2*(1-0.9976)=2*0.0024=0.0048
    SolutionASAP | Mar 13, 2020, 00:29 AM
  • Excel calculation has attached. Please check and that file. PS: Please release my payment with 10/10 ratings. Do you have any new work?
    SolutionASAP | Mar 13, 2020, 00:30 AM
  • I will directly give it to you if I have another assignment on STA
    User_24281 | Mar 13, 2020, 21:14 PM
  • Hai, I just want to make sure. For the number 2d it supports the conclusion in part C right?
    User_24281 | Mar 13, 2020, 21:16 PM
  • Sure. Pleas create new request. I can help you. Conclusion of part c right and no worried.
    SolutionASAP | Mar 14, 2020, 00:31 AM
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